Question

two coins are tossed find the provability of getting atleast one head.
Give solution with method.


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Answer 1

If 2coins are tossed then the above possibilitys are possible.
head, head
head, tale
tale, tale
tale, head

therefore we can see that from the above conditions head of occures 3 times so therefore the probability is 3 by 4

Answer 2

Given total number of coins tossed = 2.

Total possible outcomes n(S) = {HH,TT,TH,HT}.

= > n(S) = 4.

Let A be the event of getting atleast one head.

= > n(A) = {HH,TH,HT}

= > n(A) = 3.

Therefore, the required probability P(A) = n(A)/n(S)

= > P(A) = 3/4.

Hope this helps!