Find the value of m if x^2m=1/x^7
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This system of equation is of the form
a1x+b1y+c1=0
a2x+b2y+c2=0
where a1=2m−1,b1=3,c1=−5
and a2=3,b2=n−1 and c2=−2
For infinitely many solutions, we must have
a2a1=b2b1=c2c1
The given system of equations will have infinite number of solutions, if
32m−1=n−13=−2−5
⇒32m−1=
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