Question

Find the value of m in order that x⁴-2x³+3x²-mx+6 may be divisible by x-3

Answer 1

x - 3 = 0

x = 3

p(x) = x⁴-2x³+3x²-mx+6 = 0

p(3) = (3)⁴ - 2(3)³ + 3(3) - m(3) + 6=0

p(3) = 81 - 54 + 9 - 3m + 6 = 0

p(3) = 96 - 54 - 3m = 0

p(3) = 42 - 3m = 0

p(3) = 42 = 3m

3m = 42

m = 42/3

m = 14

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