find the value of 'm'..... please.... tomorrow is my exam
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Answered by
1
Answer:
use the formula of b^2-4ac=0
Step-by-step explanation:
(5+m)^2-64(m-2)=0
25+m^2+10m-64m+128=0
m^2-54m+153=0
m^2-51m-3m+153=0
m(m-51)-3(m-51)=0
(m-3)(m-51)=0
m=3 or 51
GurpreetAmbarsariya:
thankyou:)
Answered by
1
Answer:
Step-by-step explanation:
for having equal roots, the condition is:
D = 0
D= b²-4ac
b²- 4ac = 0
putting values gives
(5+m)² - 64(m-2) = 0
25 + m² + 10m - 64m +128=0
m² -54m + 153 = 0
m² - 51m - 3m + 153 = 0
m( m - 51 ) - 3( m - 51 )=0
(m - 3)(m - 51) = 0
m = 3 or 51
hope it helps you
kindly mark it brainliest.
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