Find the value of m so that (2x-1) is a factor of 8x^4+ 4x^3- 16x^2+ 10x + m
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Answered by
57
zero of the divisor
= 2x-1 = 0
= 2x = 1
x=1/2
p(x) = 8x^4 - 4x^3 - 16x^2 + 10x + m
p(1/2) = 8*(1/2)^4 - 4*(1/2)^3 - 16*(1/2)^2 + 10*1/2 + m = 0
= 8*1/16 - 4*1/8 - 16*1/4 + 5 + m = 0
= 1/2 - 1/2 - 4 + 5 +m =0
= 1+m = 0
= m = -1
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= 2x-1 = 0
= 2x = 1
x=1/2
p(x) = 8x^4 - 4x^3 - 16x^2 + 10x + m
p(1/2) = 8*(1/2)^4 - 4*(1/2)^3 - 16*(1/2)^2 + 10*1/2 + m = 0
= 8*1/16 - 4*1/8 - 16*1/4 + 5 + m = 0
= 1/2 - 1/2 - 4 + 5 +m =0
= 1+m = 0
= m = -1
can u mark as brainliest plzzzz
harshit244:
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Answered by
14
given,
2x-1 is a factor of 8x^4+4x³-16x²+10x+m
so by substituting x=+1/2 the given polynomial will be equal to zero
so 8(1/2)^4+4(1/2)³-16(1/2)²+10(1/2)+m=0
(8/16)+(4/8)-(16/4)+(10/2)+m=0
(1/2)+(1/2)-4+5+m=0
1+5-4+m=0
=>m=-2
2x-1 is a factor of 8x^4+4x³-16x²+10x+m
so by substituting x=+1/2 the given polynomial will be equal to zero
so 8(1/2)^4+4(1/2)³-16(1/2)²+10(1/2)+m=0
(8/16)+(4/8)-(16/4)+(10/2)+m=0
(1/2)+(1/2)-4+5+m=0
1+5-4+m=0
=>m=-2
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