Question

find the value of m so that m+2,4m-6 and 3m- 2 are three consecutive terms of an AP

Answer 1

4m-6-m-2=3m-2-4m+6
==>3m-8=-m+4
==>4m=12
==>m=3

Answer 2

Here a = m+2
a2 = 4m-6
a3= 3m - 2
Now .we know that in consecutive ap
a2-a1= a3-a2
so,
4m-6 - m-2 = 3m-2-4m+6
3m-8= 4-m
3m +m = 4+8
4m=12
m=3 ....