Question

find the value of M so that the following equation have equal roots mx^2+3x-5=0​

Answer 1

Since the given equation has equal toote, it's discriminant must be equal to zero.

So, D = 0

=> b^2 - 4ac = 0

=> 3^2 - 4(m)(-5) = 0

=> 9 + 20m = 0

=> 20m = -9

=> m = -9/20

Answer 2

Equation: mx^2 + 3x - 5 = 0

For equal roots discriminant must be zero.

That is, D = 0

(3)^2 - 4(m)(-5) = 0

9 + 20m = 0

20m = -9

m = -9/20

Hence, the value of m for which the given equation have equal roots is: m = -9/20