Question

Find the value of m so that the quadratic equation mx(x-7)+49=0 has two equal roots

Answer 1

i hope u will undrstand

Answer 2

Answer:

The value of m is 4 or 0.

Step-by-step explanation:

we have to find the value of m so that the quadratic equation mx(x-7)+49=0 has two equal roots.

$mx(x-7)+49=0$

$mx^2-7mx+49=0$

Compare above equation with the general quadratic equation $ax^2+bx+c=0$, we get

a=m, b=-7m, c=49

As we know if the quadratic equation has equal roots then the discriminant will be equals to 0 i.e

$b^2-4ac=0$

⇒ $(-7m)^2-4(m)(49)=0$

⇒ $49m(m-4)=0$

implies m=4, 0