find the value of m so that the quadratic equation mx(x-7)+49=0has two equal roots
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Answered by
19
Hello !
The given equation is mx ( x - 7 ) + 49 = 0
mx ( x - 7 ) + 49 = 0
mx² - 7mx + 49 = 0
Here,
a = m , b = -7m and c = 49.
Discriminant ( D ) = 0
B²-4AC = 0
(-7m)² - 4 × m × 49 = 0
49m² - 196m = 0
49m ( m - 4 ) = 0
( m - 4 ) = 0
m = 4.
The given equation is mx ( x - 7 ) + 49 = 0
mx ( x - 7 ) + 49 = 0
mx² - 7mx + 49 = 0
Here,
a = m , b = -7m and c = 49.
Discriminant ( D ) = 0
B²-4AC = 0
(-7m)² - 4 × m × 49 = 0
49m² - 196m = 0
49m ( m - 4 ) = 0
( m - 4 ) = 0
m = 4.
Answered by
2
mx(x-7)+49=0
mx²-7mx + 49 = 0
d = 0
b² -4ac = 0
(-7m)²-4×m×49 = 0
49m² - 196m = 0
49m ( m -4) = 0
m = 4.
mx²-7mx + 49 = 0
d = 0
b² -4ac = 0
(-7m)²-4×m×49 = 0
49m² - 196m = 0
49m ( m -4) = 0
m = 4.
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