Question

Find the value of m so that the
quadratic equation mx (x – 7) + 49 = 0 has
two equal roots.​

Answer 1

mx^2 - 7mx + 49 = 0

Discriminant = 0 for equal roots.

b^2 - 4ac = 0

( - 7m) ^2 - 4×m×49 = 0

49m^2 - 196m = 0

m( 49m - 196) = 0

49m = 196

m = 196/49 = 28/7 = 4

So, $\sf{\huge {m \:= \:4}}$

Answer 2

Heya ....

☺☺☺☺

Equation = m$x^2$ -7mx + 49=0

As, this equation have equal roots.

So, D = 0

D = ($b^2$) - 4 ac

D = (-7m)(-7m) - 4(m)(49)

0 = 49$m^2$ - 196m

0 = 49m ( m - 4)

0 = m - 4

m = 4...