Question

Find the value of m which makes x^2 -8x+ m a perfect square

Answer 1

Answer:

The value of m will be 16

Step-by-step explanation:

Given :

x^2-8x+m

To find: value of m

x^2-8x+m= x^2 - (2)(4)x + m

x^2 - (2)(4)x + m =  a^2 - 2ab + b^2

Using identity (a-b)^2= a^2 + b^2 - 2ab

where a= x

          b=4

so (x-4)^2 = x^2 - 8x + m

                =   x^2 - 8x + 16