Question

find the value of M with x square x square + 3 xy + x m y - which is the linear equation coefficient

Answer 1

x² + 3xy + x + my - m 

from the given two degree equation 

x² + 3xy + x + my - m = (ax + by + c)(dx + c) 

x² + 3xy + x + my - m 

= (ad)x² + (ae)x + (bd)xy + (be)y + (dc)x + (ce) 

Both side compare 

x² → ad = 1 

xy → bd = 3 

x → (ae + dc) = 1 

y → be = m 

cons → ce = -m 

(or) 

x² + x(3y + 1) + (my - m) = 0 

a = 1 b = 3y + 1 c = (my - m) 

∆ = b² - 4ac 

(3y + 1)² - 4(1)(my - m) = 0 

ay² + y(6 - 4m) + (4m + 1) = 0 

a = 9 b = 6 - 4m c = 4m + 1 

∆ = b² - 4ac 

= (6 - 4m²) - 4(9) (4m + 1) 

= 36 - 48m + 16m² - 36(4m + 1) 

9 - 12 + 4m² - 9(4m + 1) = 0 

4m² - 48m = 0 

4m (m - 12) = 0 

m = 0 m = 12


HOPE IT HELPS YOU.....

Answer 2

Hey Buddy ,,

**Learn to type the complete question correctly **