Question

find the value of 'n'?
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Answer 1

Answer:

0

Explanation:

2ax-x^2=-(x^2-2ax+a^2-a^2)=-{(x-a)^2-a^2}=a^2-(x-a)

Now,

integ dx/

$\sqrt{ {a}^{2} - {(x - a}^{2} }$

${sin}^{ - 1} ( \frac{x}{a} - 1 )$

there for,

l.h.s.=r.h.s.

then,

n=0