find the value of n
(-3)power n+1 ×(-3)power 5 =(-3)power-4
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22
(-3)^n+1×(-3)^5=(-3)^-4
a^m×a^n=a^m+n
(-3)^n+1+5=(-3)^-4
(-3)^n+6=(-3)^-4
where bases are equal there powers are equal so
n+6=-4
n=-4-6
n=-10
Answered by
6
Step-by-step explanation:
Given: (-3)^n+1×(-3)^5 =(-3)^-4
Solution: (-3)^n+1×(-3)^5=(-3)^-4
a^m×a^n= a^m+n
(-3)^n+1+5=(-3)^-4
(-3)^n+6=(-3)^-4
Where bases are equal there powers
are equal so
n+6=-4
n=-4-6
n=-10
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