Question

find the value of n
grade 8th
math

Answer 1

Answer:

year 2021

corona (covid - 19)

year 2091

corona ji 123 (covid - 98)

Answer 2

Answer:

n = -1

Step-by-step explanation:

Given Question,

To find the value of n

Given Equation:

${( \frac{ - 2}{3} )}^{4} \div {(\frac{ - 2}{3} )}^{3} = {( \frac{ - 3}{2} )}^{n}$

Solution:

${( \frac{ - 2}{3} )}^{4} \div {(\frac{ - 2}{3} )}^{3} = {( \frac{ - 3}{2} )}^{n}$

$= > {( \frac{ - 2}{3} )}^{4} \div {(\frac{ - 2}{3} )}^{3} = {( \frac{ - 2}{3} )}^{ - n}$

Since,

${a}^{x} \div {a}^{y} = {a}^{x - y}$

Hence,

$= > { (\frac{ - 2}{3}) }^{4 - 3} = { (\frac{ - 2}{3}) }^{ - n}$

As the bases are same,

Therefore,

=> 4 - 3 = -n

=> 1 = -n

=> n = -1

Result:

Hence, the required value of n is -1 (Ans)