Math, asked by sef6902, 1 year ago

find the value of n if 2^2n-4 = 64^n-1

Answers

Answered by DINESHDHANUSH
1
2^2(5) -4 = 64^5-1
2^6 =64^4
Answered by harshu44
1
Hello Dear!!!!

Here's your answer...

2^2n-4 = 64^n-1

64 can be written as 2^6

2^2n-4 = 2^6(n-1)

bases are same...so powers should be equated

2n-4 = 6n-6

2(n-2) = 6(n-1)

n-2 = 3(n-1)

n-2 = 3n-3

n-3n = -3+2

-2n = -1

n = 1/2


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