find the value of n if 2^2n-4 = 64^n-1
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Answered by
1
2^2(5) -4 = 64^5-1
2^6 =64^4
2^6 =64^4
Answered by
1
Hello Dear!!!!
Here's your answer...
2^2n-4 = 64^n-1
64 can be written as 2^6
2^2n-4 = 2^6(n-1)
bases are same...so powers should be equated
2n-4 = 6n-6
2(n-2) = 6(n-1)
n-2 = 3(n-1)
n-2 = 3n-3
n-3n = -3+2
-2n = -1
n = 1/2
Here's your answer...
2^2n-4 = 64^n-1
64 can be written as 2^6
2^2n-4 = 2^6(n-1)
bases are same...so powers should be equated
2n-4 = 6n-6
2(n-2) = 6(n-1)
n-2 = 3(n-1)
n-2 = 3n-3
n-3n = -3+2
-2n = -1
n = 1/2
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