Question

find the value of n if 2n +1,n²+n+1,3n²- 3n+3 are consecutive term of ap​

Answer 1

Answer:

if a, b, c are in AP

b-a=c-b

2b=a+c

2(n2+n+1)= 2n +1+3n2-3n+3

2n2 +2n+2=3n2-n+4

n2-3n+2=0

n2-n-2n+2=0

n(n-1)-2(n-1)=0

$n-1)-2(n-1)=0

(n-1)(n-2)=0

n=1,n=2