Question

find the value of n if

$( \frac{ - 11}{13}) {}^{3} \times ( \frac{ - 11}{13}) {}^{21 } = ( \frac{ - 11}{13}) {}^{n }$

Answer 1

${( \frac{ - 11}{13} )}^{3} \times {( \frac{ - 11}{13} )}^{21} = {( \frac{ - 11}{13} )}^{n} \\ {( \frac{ - 11}{13} )}^{24} = {( \frac{ - 11}{13}) }^{n} \\ n = 24$
your answer is here ✌✌✌✌✌✌✌

Answer 2

hey your ans is here


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we know that same numbers having different powers so their powers get added

so

(-11/13)3×(-11/13)21=(-11/13)n
(-11/13)^21+3=(-11/13)^n. [ -11/13 gets cancelled from both sides]

ans

n=24

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