Question

Find the value of'n' in each ofthe following :
(i)(2/3)^3*(2/3)^5=(2/3)^n-2​

Answer 1

Answer:

$(\frac{2}{3} )^{3} \times (\frac{2}{3} )^{5} = (\frac{2}{3} )^{n - 2} \\ \\ since \: bases \: are \: same \: powers \: are \: equal \\ \\ therefore \\ \\ 3 \times 5 = n - 2 \\ 15 = n - 2 \\ 15 - 2 = n \\ n = 13$

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