find the value of n in given triangle
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n factorial is given by.
n!= n×(n−1)×(n−2)×........ ×3×2×1.
n! =n×(n−1)!
1!= ...
2!= 2×1=2.
3!= 3×2×1=6.
4!= 4×3×2×1=24.
5!= 5×4×3×2×1=120.
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Hope it helps you dear friend
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