Math, asked by shabanasheikh97393, 2 months ago

find the value of n!/r!(n-r)! when n= 8, r=6​

Answers

Answered by bathijahetal
0

Answer:

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Answered by gangadharnaidu1993
1

Answer:

n!/r!(n-r)!

n=8,r=6

8!/6!(8-6)!

=>8!/6!*2!

=>(8*7*6*5*4*3*2*1)/(6*5*4*3*2*1)*2

=>(8*7)/2

=>4*7=>28

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