Question

find the value of n, where n is an integer. 2^(n-5)*6^(2n-4)=1/12^4*2

Answer 1

2^(n-5) x 6^(2n-4)=1/12^4 x 2

RH = LH

Step 1 Simplefy RH side

=1/((2 x 6)^4 x 2)

=1/2^5 x 6^4

=2^-5x 6^-4

Step 2

2^(n-5) x 6^(2n-4) = 2^-5 x -6^-4

LH and RH base is same, so the power also same

2^(n-5) = 2^-5

n-5 = -5

n=0

Answer 2

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