Question

find the value of of [ 4-¹ + 3-¹ + 6-²]-¹
plssss​

Answer 1

Answer:

$({4}^{ - 1} + {3}^{ - 1} + {6}^{ - 2} ) {}^{ - 1}$

$( \frac{1}{4} + \frac{1}{3} + \frac{1}{36} ) {}^{ - 1}$

$(\frac{9 + 12 + 1}{36}) {}^{ - 1}$

$( \frac{11}{18} ) {}^{ - 1}$

$\frac{18}{11}$

Answer 2

Answer:

1/(1/4+1/3+1/3)

1(7/12+1/36)

1/21+1/36

36/22

18/11 ans