Question

find the value of p(0) and p(1) for p(x)= x²​

Answer 1

p(0) =(0) +1

p(1)) = (1) -1+1= 1

Answer 2

Answer:

• value of p(0) for p(x) = x^2-x+1

so we will put 0 in place of x

0^2-0+1

0-0+1

your answer is 1

• value of p(1) for p(x) = x^2-x+1

again we will put 1 in place of x

1^2-1+1

1-1+1

0+1

your answer is 1