find the value of p(2√2),if p (x)=x2-2√2x+1
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Heya!!
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If p(x) = x^2 - 2√2 x + 1
Then p(2√2) = (2√2)^2 - 2√2(2√2) + 1
= 8 - 8 + 1
= 1
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Hope it helps u :)
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If p(x) = x^2 - 2√2 x + 1
Then p(2√2) = (2√2)^2 - 2√2(2√2) + 1
= 8 - 8 + 1
= 1
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Hope it helps u :)
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0
Answer:
Madarchod kuch bhi answer mat de
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