Math, asked by Kulbhushan15, 1 year ago

Find the value of p(-2/3) for p(y) = 2y^3 - y^2 - 13y - 6 ?

Answers

Answered by Swarup1998

4

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Swarup1998: i wrote (-24/27)

Swarup1998: but sorry that be (-16/27)

Swarup1998: then...

Swarup1998: -16/27 -4/9 +26/3 -6

Swarup1998: = (-16 - 12 + 234 -162)/27

Swarup1998: = -44/27

Swarup1998: please... take this answer...

Swarup1998: my posted answer is wrong...

Swarup1998: this one is correct...

Swarup1998: take down this one...

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