Find the value of p(-2/3) for p(y) = 2y³ - y² - 13y - 6
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p (-2/3)= 2 (-2/3)^3 -(-2/3)^2 -13 (-2/3) -6
= 2 (-8/27) -(4/9) + 26/3 - 6
= -16/27 -4/9 + 26/3 -6
= -16/27 - 12/27 + 234/27 - 162/27
= (-16-12+234-162)/27
= 44/27
= 1 17/27.
= 2 (-8/27) -(4/9) + 26/3 - 6
= -16/27 -4/9 + 26/3 -6
= -16/27 - 12/27 + 234/27 - 162/27
= (-16-12+234-162)/27
= 44/27
= 1 17/27.
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