Question

find the value of p (2/5)^3×(2/5)^-6 =(2/5)^2P-1​
plzz help

Answer 1

Answer:

-1

Step-by-step explanation:

(2/5)^3-6=(2/5)^2p-1

there fore- 2p-1= -3

=>2p= -2

=>p= -1

Answer 2

Step-by-step explanation:

Given -

(2/5)^3 × (2/5)^-6 = (2/5)^2p - 1

To Find -

Value of p

As we know that :-

• a^p × a^q = a^p+q

It means,

» (2/5)^3 × (2/5)^-6 = (2/5)^2p-1

» (2/5)^3-6 = (2/5)^2p-1

» (2/5)^-3 = (2/5)^2p-1

As we see that here base is equal

So,

» - 3 = 2p - 1

» - 3 + 1 = 2p

» - 2 = 2p

» p = -2/2

• » p = -1

Hence,

The value of p is -1

Verification -

(2/5)^3 × (2/5)^-6 = (2/5)^2p-1

» (2/5)^3-6 = (2/5)^2×-1 -1

» (2/5)^-3 = (2/5)^-2-1

» (2/5)^-3 = (2/5)^-3

Hence,

Verified..

Formula Used :-

• a^p × a^q = a^p+q

Some related formulas :-

• a^p ÷ a^q = a^p-q
• (a^p)^q = a^pq
• a^pb^p = (ab)^p