Q. A circular field has perimeter 600 m.
A plot in the shap of a square
having its vertices on the
circumference is marked in the
field. calculate the area of the
square field.
Answers
Answer:
Step-by-step explanation:
Hey there !!
Let the radius of the circular field be r m .
Perimeter of the circular field = Circumference of the field .
=> 660 = 2πr .
\begin{lgathered}\begin{lgathered}= > 660 = 2 \times \frac{22}{7} \times r. \\ \\ = > r = \frac{660 \times 7}{2 \times 22} . \\ \\ \therefore r = 105m .\end{lgathered}\end{lgathered}=>660=2×722×r.=>r=2×22660×7.∴r=105m.
•°• Diameter of the circular field = 2 × 105 = 210 m.
Vertices of the square plot lie on the circumference of the circle .
•°• Diameter of the circular field = Diagonal of the square plot .
=> 210 = BD .
In right ∆ABD,
AB² + AD² = BD² .
=> AB² + AB² = (210)² .
=> 2AB² = 210 × 210 .
=> AB² = ( 210 × 210 )/2 .
•°• AB² = 22050 m² .
•°• side² = 22050 m² .
✔✔ Hence, area of the square plot is 22050 m² ✅✅ .