Math, asked by shraddhakatiyar10102, 10 months ago

Q. A circular field has perimeter 600 m.
A plot in the shap of a square
having its vertices on the
circumference is marked in the
field. calculate the area of the
square field.​

Answers

Answered by speketi83siri
0

Answer:

Step-by-step explanation:

Hey there !!

Let the radius of the circular field be r m .

Perimeter of the circular field = Circumference of the field .

=> 660 = 2πr .

\begin{lgathered}\begin{lgathered}= > 660 = 2 \times \frac{22}{7} \times r. \\ \\ = > r = \frac{660 \times 7}{2 \times 22} . \\ \\ \therefore r = 105m .\end{lgathered}\end{lgathered}=>660=2×722×r.=>r=2×22660×7.∴r=105m.

•°• Diameter of the circular field = 2 × 105 = 210 m.

Vertices of the square plot lie on the circumference of the circle .

•°• Diameter of the circular field = Diagonal of the square plot .

=> 210 = BD .

In right ∆ABD,

AB² + AD² = BD² .

=> AB² + AB² = (210)² .

=> 2AB² = 210 × 210 .

=> AB² = ( 210 × 210 )/2 .

•°• AB² = 22050 m² .

•°• side² = 22050 m² .

✔✔ Hence, area of the square plot is 22050 m² ✅✅ .

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