Find the value of P(√2), if P(x) = x^3-3x^2-7x+2
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for the value of P = √2
p(√2) = (√2)³- 3(√2)² - 7(√2) + 2
P(√2) = 2√2 - 6 - 7√2 + 2
P(√2) = -5√2 -4
P(√2) = -1√2(1 + 2√2)
p(√2) = (√2)³- 3(√2)² - 7(√2) + 2
P(√2) = 2√2 - 6 - 7√2 + 2
P(√2) = -5√2 -4
P(√2) = -1√2(1 + 2√2)
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