find the value of p
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Given
2x²+px+8=0
Here,
a =2, b =p and c = 8
Discrimination D is given by
D = ( b² - 4ac )
= p² -4 * 2 * 8
= (p²-64)
If D ⩾ 0, the roots of equation will be real
= (p² -64) ⩾ 0
= (p+8) (p-8) ⩾ 0
= p ⩾ 8 and p ⩽ -8
Thus the roots of the equation are equal for p ⩾ 8 and p ⩽ -8
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