find the value of p and q:
(a) x^2 + 4x - p = (x - q) (x + 7)
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×+7is a factor of x^2+4x-p
x=-7 we get- 7^2+4×-7-p=0
p=21
x^2+4x-21
x^2+7x-3x-21
x (x+7)-3 (x+7)
(x-3)(x+7)
p=21 & q=3
x=-7 we get- 7^2+4×-7-p=0
p=21
x^2+4x-21
x^2+7x-3x-21
x (x+7)-3 (x+7)
(x-3)(x+7)
p=21 & q=3
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