Math, asked by suraj7325gjufnj, 1 year ago

find the value of p and q:
(a) x^2 + 4x - p = (x - q) (x + 7)

Attachments:

Answers

Answered by subodhKant
2
×+7is a factor of x^2+4x-p
x=-7 we get- 7^2+4×-7-p=0
p=21
x^2+4x-21
x^2+7x-3x-21
x (x+7)-3 (x+7)
(x-3)(x+7)
p=21 & q=3
Similar questions