Question

find the value of P bracket minus 2 upon 3 for P bracket Y is equal to 2 y cube minus y square - 13 Y - 6​

Answer 1

mark as the brainlist please

Answer 2

The value of P(-2/3) is $\dfrac{44}{27}$.

Step-by-step explanation:

The given function is

$P(y)=2y^3-y^2-13y-6$

We need to find the value of P(-2/3).

Substitute $x=-\frac{2}{3}$ in the above function.

$P(-\dfrac{2}{3})=2(-\dfrac{2}{3})^3-(-\dfrac{2}{3})^2-13(-\dfrac{2}{3})-6$

$P(-\dfrac{2}{3})=2(-\dfrac{8}{27})-(\dfrac{4}{9})-\dfrac{-26}{3}-6$

$P(-\dfrac{2}{3})=-\dfrac{16}{27})-\dfrac{4}{9}+\dfrac{26}{3}-6$

Taking LCM,

$P(-\dfrac{2}{3})=\dfrac{-16-12+234-162}{27}$

$P(-\dfrac{2}{3})=\dfrac{44}{27}$

Therefore, the value of P(-2/3) is $\dfrac{44}{27}$.

#Learn more

If p(x)=x^3+3x^2-2x+4, then find the value of p(2) + p(-2) -p(0)​

https://brainly.in/question/11793878