Find the value of p for when the curves x2=9p(9-y) and x2=p(y+1) cut each other at right angles
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Solution:
Given:
x² = 9p(9-y),..(i)
x²=p(y+1)..(ii)
hence,.
=>9p(9-y) =p(y+1)
=> 9(9-y)=y+1
=>81-9y=y+1
=>0=y+1-81+9y
=>0=10y-80
=> -10y=-80
=> y=8,.....(iii)
(i)=> x²=9p(9-y)
=>x²=9p(9-8)
=>x²=9p...(iv)
=>
Hope it Helps,.
Given:
x² = 9p(9-y),..(i)
x²=p(y+1)..(ii)
hence,.
=>9p(9-y) =p(y+1)
=> 9(9-y)=y+1
=>81-9y=y+1
=>0=y+1-81+9y
=>0=10y-80
=> -10y=-80
=> y=8,.....(iii)
(i)=> x²=9p(9-y)
=>x²=9p(9-8)
=>x²=9p...(iv)
=>
Hope it Helps,.
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