Question

find the value of p for which one root of the quadratic equation px2-14x+8=0 is 6 times the other

Answer 1

Px^2-14x+8=0 let a and b be the roots of the equation b=6a sum of roots = -b/a product of roots = c/a a=p , b=-14 , c=8
a+b=14/p
ab=8/p


a+6a=14/p
7a=14/p
a=2/p

a*6a=8/p
6a^2=8/p
3a^2=4/p


3*(2/p)^2=4/p

3*4/p^2=4/p

p=3

Hope you found the answer helpful pls mark as brainliest :-)

Answer 2

Let one zero be a and other zero be 6a
A+6a=14/p
7a=14/p
a=2/p
Product of zeros
6a^2=8/p
just put value of a in it and you will get your answer