Find the value of p, for which one root of the quadratic equation px3-14x+8=0 is 6 time the other
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Answer:3
Step-by-step explanation:
one root is x,the other is 6x
x+6x=14/p
x=2/p (1)
x*6x=8/p
6x^2=8/p (2)
6*4/p2=/p
p^2/p=24/8
p=3
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