Question

Find the value of p for which one zero of the polynomial px2^- 144 x + 8 is eleven times table other​

Answer 1

Answer: p = 198

For complete answer, please refer the attached picture.

Answer 2

Answer:

The value of p is 198.

Explanation:

Let one zero = ∝

other zero = 11∝

The quadratic equation is ax²+bx+c = 0, where 'x' is a variable and 'a', 'b', and 'c' are coefficients.

The sum of the roots is equal to the negative of the second term's coefficient, divided by the leading coefficient.

Here,

a = p

b = -144

c = 8

From the question, we have

$\alpha+11 \alpha = \frac{-b}{a} \\12 \alpha = \frac{144}{p} \\\alpha = \frac{12}{p}$

The third term divided by the first term represents the product of roots.

$\alpha*11 \alpha = \frac{c}{a} \\11 \alpha^{2} = \frac{8}{p} \\11 *\frac{12}{p}*\frac{12}{p} = \frac{8}{p}\\p = 198$

The value of p is 198

Multiplication:

To find the sum of two or more integers, mathematicians multiply the numbers. It is a basic mathematical method that is widely used in daily life. The multiplicand, multiplier, and product are the elements of it. The first number is the multiplicand, the second number is the multiplier, and the result is the product.  The outcome of multiplying two or more numbers is referred to as the product of those numbers, and the factors are the quantities that are multiplied. Multiplying the numbers makes it simpler to add the same number repeatedly. It is the technique in many fields of mathematics, including algebra, calculus, equations, and others.

To learn more about multiplication visit:

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