From a group of 15 chess players 8 players are selected by lot to represent the group at a convention. What is the probability that the 8selected include 3of the 4best players in the group?
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Step-by-step explanation:
A wins the series the following ways. In all these cases the last match has been win by A
(a) A wins all the games in a row. The number of ways. =1
(b) A wins the last game on the remaining 4 games played. A wins three games while B wins one.
The no. of ways .
3!
4!
.
3!
4×3!
.4
(c) A wins the last game on the remaining 5 games played. A wins three while B wins two.
The number of ways .
3!.2!
5!
=10.
(d) A wins the last game on the remaining 6 games played. A wins three while B wins three.
The number of ways .
3!.3!
5!
=20
∴ The total no. of ways in which the series can be won by A=1+4+10+20=35
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