Find the value of p for which quardratic equation (p+1)x²-6(p+1)x+3(p+q) has equal root .
atulrajcool:
there should be a digit in place of q
i am sorry for the mistake.
ohh ho
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(p+1)2-6(P+1)x+3(p+q)=0
equal roots mean b2=4ac(in quadratic ax2+bx+c=0)
hence root is x=-b/2a
apply to above
root is x =6(p+1)/2(p+1)=3
and to find p we use b2=4ac
36(p+1)2=4×(p+1)×3(p+q)
3(p+1)=p+q
2q=q-3
p=q-3/2
p=3,q=9
equal roots mean b2=4ac(in quadratic ax2+bx+c=0)
hence root is x=-b/2a
apply to above
root is x =6(p+1)/2(p+1)=3
and to find p we use b2=4ac
36(p+1)2=4×(p+1)×3(p+q)
3(p+1)=p+q
2q=q-3
p=q-3/2
p=3,q=9
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