find the value of p for which the equation is px²-5x+p has equal roots.
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if the equation is of form ax^2+ bx +c =0
sum of roots = -b/a,
product of roots = c/a
by question
let q be the root of equation given
sum of roots =q +q =-(-5)/p
2q = 5/p
q=5/2p~~~~@1
product of roots = q×q = p/p = 1
q^2 =1
q=1 or q= -1
substitute if q =1 in @1
p=2/5q=2/5
if q=-1
p= - 2/5
finally p= 2/5 or -2/5
hope you understood
sum of roots = -b/a,
product of roots = c/a
by question
let q be the root of equation given
sum of roots =q +q =-(-5)/p
2q = 5/p
q=5/2p~~~~@1
product of roots = q×q = p/p = 1
q^2 =1
q=1 or q= -1
substitute if q =1 in @1
p=2/5q=2/5
if q=-1
p= - 2/5
finally p= 2/5 or -2/5
hope you understood
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