Question

find the value of p for which the equation px2-5x+p=0 has equal root find the value of p

Answer 1

Answer:

Step-by-step explanation:

px2-5x+p=0

discrimant=b2-4ac

(-5)^2-4*p*p=0

25-4p^2=0

-4p^2=-25

p^2=25/4

p=5/2

Answer 2

Answer:

p = 5/2 or p = -5/2

Step-by-step explanation:

px² - 5x + p = 0

For the equation to have equal roots

⇒ Discriminant must be equal to zero

⇒ b² - 4ac = 0

Find the value of p:

(-5)² - 4(p)(p) = 0

25 - 4p² = 0

4p² = 25

p² = 25/4

p = ±√(25/4)

p = ± 5/2

Answer: p = 5/2 or p = -5/2