Question

find the value of p for which the equation px2-5x+p=0 has equal roots

Answer 1

$heya \\ \\ \\ for \: equal \: roots \: discrimnant \: must \: be \: = 0 \\ \\ \\ d = 25 - 4p {}^{2} \\ \\ d = 0 \\ \\ 4p {}^{2} = 25 \\ \\ p = 5 \div 2 \: \: \: \: \: or \: \: \: \: p = - 5 \div 2$

Answer 2

Quadratic equation:
$a {x}^{2} + bx + c = 0$


For equal roots,

${b}^{2} - 4ac = 0$

Thus,

$25 - 4(p)(p) = 0 \\ 25 - 4 {p}^{2} = 0 \\ \frac{25}{4} = {p}^{2} \\ \pm \: \frac{5}{2} = p$