Question

Find the value of p for which the equation px2-5x+p has equal real roots

Answer 1

px^2-5x+ p=0
so,b^2-4ac=0
25-4p^2=0
25=4p^2
p^2=25/4
p=5/2

Answer 2

Hi friend,

Here is your answer,
_____________________________________________________________

If there are equal roots then D = 0
D = √(b²-4ac)
q(x) = px² - 5x + p

 0   = √((-5)² - 4*p*p)
  0  = 25 - 4p²
4p² = 25
p²   = ²⁵/₄
p    = ⁵/₂
p = 2.5

For p = 2.5 the equation px² - 5x + p has equal roots.
_____________________________________________________________

★★★★ HOPE THIS HELPS YOU ★★★★
★★★★ PLS MARK ME AS BRAINLIEST ★★★★