Math, asked by bhumika9648, 3 months ago

Find the value of p for which the number 2p-1, 3p+1,11 are in AP. hence, find the numbers

Answers

Answered by tamilan1890

3

Answer:

p=9/4

Step-by-step explanation:

a= 2p-1

d= 11-(3p+1)= 11-3p-1

= 10-3p

third term is 11

a+2d = 11

2p+2(10-3p)=11

2p+20-6p= 11

-4p= 11-20

-4p= -9

p=9/4

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