Question

find the value of p for which the polynomial x^3+4x^2-px+8 is exactly divisible by x-2 {for class 10}

Answer 1

Since,
X-2=0
:.x=2=g(x)
Now,
P(x)=x³+4x²-px+8
:. putting value
P(2)=2³+4(2)²-p(2)+8=0
8+16-2p+8=0
32-2p=0
-2p=-32
P=-32/-2=16
(ÆÑẞWĒR)