Question

Find the value of 'p' for which the quadratic equation has real roots 2x^2 + 3x + p =0

Answer 1

$\large\bf\underline \blue {To \: \mathscr{f}ind:-}$

we need to find the value of p

$\huge\bf\underline \red{ \mathcal{S}olution:-}$

● Condition for equal roots :-

When roots are real and equal then Discriminant is equal to 0.

• D = 0

For a quadratic equation ax² + bx + c , expression b² - 4ac is called Discriminant.

• ★ Quadratic Equation :-2x² + 3x + p

here,

• a = 2
• b = 3
• c = p

⇛ b² - 4ac = 0

⇛ (3)² - 4 × 2 × p = 0

⇛ 9 - 8p = 0

⇛ - 8p = -9

⇛ p = 9/8

Hence,

• Value of p is 9/8

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Answer 2

Question :-

Find the value of 'p' for which the quadratic equation has real roots 2x^2 + 3x + p =0.

Solution :-

• Discriminant → b² - 4ac = 0

here,

a = 2

b = 3

c = p

→ b² - 4ac = 0

→ (3)² - 4 × 2 × p = 0

→ 9 - 8p = 0

→ - 8p = -9

→ p = 9/8

Hence,

• p = 9/8 $\sf$