Question

Find the value of 'p' for which the quadratic equation has real roots 2x^2 + 3x + p =0​

Answer 1

Explanation:

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Answer 2

${ \huge{ \underline{ \underline{ \sf{ \green{GivEn : }}}}}}$

• A quadratic equation __2x² + 3x + p

${ \huge{ \underline{ \underline{ \sf{ \green{To \: find :}}}}}}$

• The value of p

${ \huge{ \underline{ \underline{ \sf{ \green{SoluTion : }}}}}}$

We know that,

When roots are real then Discriminant is equal to 0.

D = 0 = b² - 4ac

Given that,

A quadratic equation __2x² + 3x + p

Where,

a = 2

b = 3

c = p

Now, find the value of p

⟶ b² - 4ac = 0

⟶(3)² - 4 × 2 × p = 0

⟶ 9 - 8p = 0

⟶ - 8p = -9

⟶ p = 9/8

Hence, value of p is = 9/8

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Verification :-

⟶ b² - 4ac = 0

⟶ (3)² - 4 × 2× 9/8 = 0

⟶ 9 - 9 = 0

⟶ 0 = 0

L.H.S = R.H.S

(verified)