Question

Find the value of p for which the quadratic equation x(x-4)+p=0

Answer 1

Answer:

x(x - 4)+p = 0

It can be written as

x^2 - 4x + p =0

as,

a= 1, b= -4, c= p

d= b^2 - 4ac

By putting the values,  

= (-4)2 - 4(1)(p)

= 16 - 4p

4p = 16

p = 16/4 = 4.