Question

Find the value of p for which the quadratic equation x(x-4) x p+0 has real roots.

Answer 1

x(x-4)+p=0

x²-4x+p=0

If the equation has real roots than
=>D>0

D=b²-4ac

D=(-4)²-4×1×p
D=16-4p

now,D>0

16-4p>0
-4p>-16
p>4


the value of p can be any real number which is greater than 4