Question

find the value of p for which the two roots of the quad equa x2 -2(p-2)x+(4p-3)=0​

Answer 1

Quadratic Equation $ax^2+bx+c=0$

⇅⇅

$D/4=b^2-ac$ (nature of the roots)

$D/4$ must be greater than 0. (For real $x$ )

$(p-2)^2-(4p-3)=p^2-8p+7$

$(p-1)(p-7)>0$

∴$p<1$ or $p>7$

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